x=4,x^2-3x+5=

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Solution for x=4,x^2-3x+5= equation: 



x=4.x^2-3x+5=

We move all terms to the left:

x-(4.x^2-3x+5)=0

We get rid of parentheses

-4.x^2+x+3x-5=0

We add all the numbers together, and all the variables

-4x^2+4x-5=0

a = -4; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-4)·(-5)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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